A rectangular prism has edges 3, 1 1/2, and 6 cm. Sketch it and find its volume.
B = 3 × 3/2 = 9/2 cm²; V = B × 6 = 27 cm³.
I can choose the correct geometric measure and justify the units.
Read the requested quantity first and identify the relevant model. Two matching triangles form a parallelogram, so A = (base × perpendicular height)/2. A slanted side is not necessarily the height. Label area in square units. Explain why the units and the final value fit the situation.
A rectangular prism has edges 3, 1 1/2, and 6 cm. Sketch it and find its volume.
B = 3 × 3/2 = 9/2 cm²; V = B × 6 = 27 cm³.
A 3 cm by 5 cm base and 4 cm height form an open-top box. Draw its net and find the material area. Ignore tabs and overlap.
Closed surface area = 2(15+12+20) = 94. Remove the top area 15: 79.
Work in order. Start with the foundations, then build toward explanation and application.
Sketch a triangle with base 16 cm and perpendicular height 3 cm. Find its area.
A rectangular prism has edges 6, 1, and 5 cm. Sketch it and find its volume.
A 6 cm by 2 cm base and 2 cm height form a closed box. Draw its net and find the material area. Ignore tabs and overlap.
An L-shaped garden is a 11 m by 11 m rectangle with an 7 m by 7 m corner rectangle removed. Sketch and find the garden area.
A square pyramid has base edge 8 cm. Each triangular face has perpendicular face height 7 cm. Draw a net and calculate total surface area.
Sketch a triangle with base 8 cm and perpendicular height 2 cm. Find its area.
A rectangular prism has edges 2 1/2, 2 1/2, and 3 cm. Sketch it and find its volume. Show both lwh and Bh.
A 4 cm by 7 cm base and 3 cm height form an open-top box. Draw its net and find the material area. Ignore tabs and overlap.
A 11 m by 7 m rectangle has a right-triangle corner removed with perpendicular legs 3 m and 4 m. Sketch the remaining polygon and find its area.
A square pyramid has base edge 14 cm. Each triangular face has perpendicular face height 10 cm. Draw a net and calculate total surface area. Explain why the vertical pyramid height is not needed.
A = bh/2 = 16 × 3 ÷ 2 = 24. Two such triangles make a parallelogram.
B = 6 × 1 = 6 cm²; V = B × 5 = 30 cm³.
Closed surface area = 2(12+12+4) = 56.
Outer area 121 minus cutout 49 = 72.
Base = 64; each triangle = 8 × 7 ÷ 2 = 28; add four triangles to get 176.
A = bh/2 = 8 × 2 ÷ 2 = 8. Two such triangles make a parallelogram.
B = 5/2 × 5/2 = 25/4 cm²; V = B × 3 = 75/4 cm³.
Closed surface area = 2(28+12+21) = 122. Remove the top area 28: 94.
Whole rectangle 77; remove triangle 6; difference 71.
Base = 196; each triangle = 14 × 10 ÷ 2 = 70; add four triangles to get 476.