Fill a prism 3/2 × 2 × 1 units with cubes of edge 1/2 unit. How many cubes fit? Use their volumes to verify lwh.
Counts along edges: 3, 4, 2. Product 24; 24 × 1/8 = 3, also lwh.
I can connect volume and nets to compare storage designs.
Read the requested quantity first and identify the relevant model. A rectangular prism has volume V = lwh = Bh, where B is base area. Fractional edge lengths still multiply. Use cubic units; surface area and volume measure different attributes. Explain why the units and the final value fit the situation.
Fill a prism 3/2 × 2 × 1 units with cubes of edge 1/2 unit. How many cubes fit? Use their volumes to verify lwh.
Counts along edges: 3, 4, 2. Product 24; 24 × 1/8 = 3, also lwh.
Draw a net for a triangular prism. Its two congruent right-triangle bases have legs 3 cm and 4 cm and hypotenuse 5 cm; prism length is 8 cm. Label all faces and find surface area.
Triangle pair: 12 cm²; rectangles: (3+4+5) × 8 = 96; total 108.
Work in order. Start with the foundations, then build toward explanation and application.
A rectangular prism has edges 7, 2, and 6 cm. Sketch it and find its volume.
Fill a prism 5/2 × 7/2 × 2 units with cubes of edge 1/2 unit. How many cubes fit? Use their volumes to verify lwh.
Draw a net for a closed 8 × 3 × 5 cm rectangular prism. Label the six faces and calculate total area.
A 5 cm by 6 cm base and 5 cm height form a closed box. Draw its net and find the material area. Ignore tabs and overlap.
A square pyramid has base edge 10 cm. Each triangular face has perpendicular face height 12 cm. Draw a net and calculate total surface area.
A rectangular prism has edges 4, 1 1/2, and 3 cm. Sketch it and find its volume.
Fill a prism 2/3 × 1 × 2 units with cubes of edge 1/3 unit. How many cubes fit? Use their volumes to verify lwh.
Draw a net for a triangular prism. Its two congruent right-triangle bases have legs 3 cm and 4 cm and hypotenuse 5 cm; prism length is 2 cm. Label all faces and find surface area.
A 8 cm by 7 cm base and 6 cm height form an open-top box. Draw its net and find the material area. Ignore tabs and overlap.
A square pyramid has base edge 6 cm. Each triangular face has perpendicular face height 10 cm. Draw a net and calculate total surface area. Explain why the vertical pyramid height is not needed.
B = 7 × 2 = 14 cm²; V = B × 6 = 84 cm³.
Counts along edges: 5, 7, 4. Product 140; 140 × 1/8 = 35/2, also lwh.
Add 2(24) + 2(40) + 2(15) = 158.
Closed surface area = 2(30+25+30) = 170.
Base = 100; each triangle = 10 × 12 ÷ 2 = 60; add four triangles to get 340.
B = 4 × 3/2 = 6 cm²; V = B × 3 = 18 cm³.
Counts along edges: 2, 3, 6. Product 36; 36 × 1/27 = 4/3, also lwh.
Triangle pair: 12 cm²; rectangles: (3+4+5) × 2 = 24; total 36.
Closed surface area = 2(56+48+42) = 292. Remove the top area 56: 236.
Base = 36; each triangle = 6 × 10 ÷ 2 = 30; add four triangles to get 156.