A rectangular prism has edges 2, 3, and 4 cm. Sketch it and find its volume.
B = 2 × 3 = 6 cm²; V = B × 4 = 24 cm³.
I can select models and explain geometric and statistical results.
Read the requested quantity first and identify the relevant model. Two matching triangles form a parallelogram, so A = (base × perpendicular height)/2. A slanted side is not necessarily the height. Label area in square units. Explain why the units and the final value fit the situation.
A rectangular prism has edges 2, 3, and 4 cm. Sketch it and find its volume.
B = 2 × 3 = 6 cm²; V = B × 4 = 24 cm³.
Reading times in minutes are 3, 4, 4, 5, 6, 15. Find the five-number summary and draw a labeled box plot. State the IQR.
Box runs from 4 to 6, median line at 9/2, whiskers to 3 and 15.
Work in order. Start with the foundations, then build toward explanation and application.
Sketch a triangle with base 16 cm and perpendicular height 5 cm. Find its area.
A rectangular prism has edges 5, 2 1/2, and 2 cm. Sketch it and find its volume.
A 5 cm by 4 cm base and 5 cm height form a closed box. Draw its net and find the material area. Ignore tabs and overlap.
Reading times in minutes are 6, 9, 9, 12, 12, 15. Describe a typical value, range, shape, and any striking value.
Reading times in minutes are 6, 9, 9, 12, 12, 15. Report n, units, and mean.
Reading times in minutes are 8, 13, 13, 18, 18, 23. Find Q1, Q3, IQR, and range.
Reading times in minutes are 6, 7, 7, 8, 9, 18. Calculate the mean and MAD. Show all absolute deviations. Interpret MAD in a sentence.
Reading times in minutes are 2, 3, 3, 4, 5, 14. Find the five-number summary and draw a labeled box plot. State the IQR.
Reading times (min): Group A [6, 7, 7, 8, 9, 18], Group B [8, 9, 9, 10, 11, 20]. Compare median and IQR. Which group reads longer typically? Which is more consistent?
Reading times in minutes are 2, 3, 3, 4, 5, 14. Write a summary with count, attribute, units, center, variability, shape, and a justified choice of measures.
A = bh/2 = 16 × 5 ÷ 2 = 40. Two such triangles make a parallelogram.
B = 5 × 5/2 = 25/2 cm²; V = B × 2 = 25 cm³.
Closed surface area = 2(20+25+20) = 130.
The values balance around the middle. Range = 15 - 6.
Sum = 63; mean = 63 ÷ 6 = 21/2.
Lower half [8, 13, 13] has median 13; upper half [18, 18, 23] has median 18. Subtract Q1 from Q3.
Distances: 19/6, 13/6, 13/6, 7/6, 1/6, 53/6; sum 53/3; divide by 6 = 53/18.
Box runs from 3 to 5, median line at 7/2, whiskers to 2 and 14.
Adding 2 shifts all values and the median by 2, but does not change Q3 - Q1.
Calculate the center and spread before interpreting them in context. Other accurate, justified summaries are acceptable.